# Finding a Remainder in JavaScript

## Hints

### Hint 1

The remainder operator `%` gives the remainder of the division of two numbers.

``````var remainder = 11 % 3; //remainder gets the value 2
``````
24 Likes

I have been struggling to get this formatted correctly. Any help would be appreciated. I put:

(11 % 3 = 2);

for my answer and it has a yellow caution triangle and says â€śBad Assignmentâ€ť pointing to the equals sign.

9 Likes

var remainder = 2 % 11;

16 Likes

The remainder operator % gives the remainder of the division of two numbers.
Example
Usage
Note

Instructions
Set remainder equal to the remainder of 11 divided by 3 using the remainder (%) operator.

1. The variable remainder should be initialized
`var remainder`

2)The value of remainder should be 2
`var remainder = 2;`

1. You should use the % operator
var remainder = 2%11;

`

15 Likes

Can anyone clarify what theyâ€™re saying here?

17 % 2 = 1 (17 is Odd)
48 % 2 = 0 (48 is Even)

â€śSet remainder equal to the remainder of 11 divided by 3 using the remainder (%) operator.â€ť

var remainder = 2%11;

Where did 11 / 3 go?

3 Likes

The above was an example. It is pretty easy but everyone has to be verbose when explaining shit here.

For 11 % 3 all you do is divide 11/3, which =3 with a remainder of 2.

can double check by 3x3=9
11-9=2(same as the remainder)

18 Likes

I have no idea what the final part of this task was on about.

I understand the following
`17 % 2 = 1 (17 is Odd)`
`48 % 2 = 0 (48 is Even)`

In the final part, the correct answer is `var remainder = 2 % 11;`, but I have no idea what this has to do with `11 / 3`.

5 Likes

I entered â€śvar remainder = 11 % 3;â€ť, which the system accepted as correct. However, looking here I see var remainder = 2 % 11; is supposed to be the correct answer. Can anyone please clarify whether 11 % 3 really is the correct syntax, and if not, why not? TIA.

12 Likes

I think itâ€™s this

``var remainder = 11 % 3;``
13 Likes

Some info about the operator https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators#Remainder_()

I think free code camp accepts the answer because the result of `2 % 11` is coincidentally the same `11 % 3`.

I got a bit confused about what they wanted, because they were talking about finding whether a number was odd or even earlier on in the tutorial.

10 Likes

There are several answeres possible you can also sollute the lesson by

``````var remainder = 11 % 3;
``````
6 Likes