# Finding a Remainder in JavaScript

## Hints

### Hint 1

The remainder operator `%`

gives the remainder of the division of two numbers.

```
var remainder = 11 % 3; //remainder gets the value 2
```

The remainder operator `%`

gives the remainder of the division of two numbers.

```
var remainder = 11 % 3; //remainder gets the value 2
```

3 Likes

I have been struggling to get this formatted correctly. Any help would be appreciated. I put:

(11 % 3 = 2);

for my answer and it has a yellow caution triangle and says â€śBad Assignmentâ€ť pointing to the equals sign.

3 Likes

var remainder = 2 % 11;

7 Likes

The remainder operator % gives the remainder of the division of two numbers.

**Example**

**Usage**

**Note**

**Instructions**

Set remainder equal to the remainder of 11 divided by 3 using the remainder (%) operator.

- The variable remainder should be initialized

`var remainder`

2)The value of remainder should be 2

`var remainder = 2;`

- You should use the % operator

var remainder = 2%11;

`

7 Likes

Can anyone clarify what theyâ€™re saying here?

17 % 2 = 1 (17 is Odd)

48 % 2 = 0 (48 is Even)

â€śSet remainder equal to the remainder of 11 divided by 3 using the remainder (%) operator.â€ť

var remainder = 2%11;

Where did 11 / 3 go?

The above was an example. It is pretty easy but everyone has to be verbose when explaining shit here.

For 11 % 3 all you do is divide 11/3, which =3 with a remainder of 2.

can double check by 3x3=9

11-9=2(same as the remainder)

10 Likes

I have no idea what the final part of this task was on about.

I understand the following

`17 % 2 = 1 (17 is Odd)`

`48 % 2 = 0 (48 is Even)`

In the final part, the correct answer is `var remainder = 2 % 11;`

, but I have no idea what this has to do with `11 / 3`

.

5 Likes

I entered â€śvar remainder = 11 % 3;â€ť, which the system accepted as correct. However, looking here I see var remainder = 2 % 11; is supposed to be the correct answer. Can anyone please clarify whether 11 % 3 really is the correct syntax, and if not, why not? TIA.

7 Likes

I think itâ€™s this

`var remainder = 11 % 3;`

9 Likes

Some info about the operator https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators#Remainder_()

I think free code camp accepts the answer because the result of `2 % 11`

is coincidentally the same `11 % 3`

.

I got a bit confused about what they wanted, because they were talking about finding whether a number was odd or even earlier on in the tutorial.

5 Likes

There are several answeres possible you can also sollute the lesson by

```
var remainder = 11 % 3;
```